(1/x^2)+(6/x)+8=0

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Solution for (1/x^2)+(6/x)+8=0 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

6/x+1/(x^2)+8 = 0

6*x^-1+x^-2+8 = 0

t_1 = x^-1

1*t_1^2+6*t_1^1+8 = 0

t_1^2+6*t_1+8 = 0

DELTA = 6^2-(1*4*8)

DELTA = 4

DELTA > 0

t_1 = (4^(1/2)-6)/(1*2) or t_1 = (-4^(1/2)-6)/(1*2)

t_1 = -2 or t_1 = -4

t_1 = -4

x^-1+4 = 0

1*x^-1 = -4 // : 1

x^-1 = -4

-1 < 0

1/(x^1) = -4 // * x^1

1 = -4*x^1 // : -4

-1/4 = x^1

x = -1/4

t_1 = -2

x^-1+2 = 0

1*x^-1 = -2 // : 1

x^-1 = -2

-1 < 0

1/(x^1) = -2 // * x^1

1 = -2*x^1 // : -2

-1/2 = x^1

x = -1/2

x in { -1/4, -1/2 }

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